-7x^2+36x+324=0

Solution for -7x^2+36x+324=0 equation:

-7x^2+36x+324=0

a = -7; b = 36; c = +324;
Δ = b2-4ac
Δ = 362-4·(-7)·324
Δ = 10368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10368}=\sqrt{5184*2}=\sqrt{5184}*\sqrt{2}=72\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-72\sqrt{2}}{2*-7}=\frac{-36-72\sqrt{2}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+72\sqrt{2}}{2*-7}=\frac{-36+72\sqrt{2}}{-14}
$